Figure shows a steel rod joined to a brass rod. Each of the rods has length of 31 cm and area of
cross-section 0.20 cm 2 . The junction is maintained at a constant temperature 50°C and the two ends are maintained at 100°C. The amount of heat taken out from the cold junction in 10 minutes after the steady state is reached in n × 10 2 J. Find ‘n’. The thermal conductivities are K steel = 46 W/m–°C and K brass = 109 W/m–°C.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(3)
Let T = 100º C
& T 0 = 50ºC
Heat = (T – T 0 ) 
(K S + K B ) × 10 × 60
= (100 – 50) × 
× (46 + 109) × 10 × 60
= 300 J
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